solve 3x-4y=7 : 5x+2y=3
solve by equating coeffcients of variable
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Step-by-step explanation:
Given that;
3x-4y =7
5x+2y =3
Now,
3x - 4y= 7 → 3x = 7 + 4y
So, X= 7/3 + 4y/3
Replacing the obtained value into the second equation;
5x + 2y =3 → 5(7/3 +4y/3) + 2y =3
So, We have;
5(7+4y) + 2y = 3(3)
35 + 20y + 2y = 9
22y = 9-35
y= (-26)/22
y= -13/11
So, X= 7/3 + 4y/3 → X= 7/3 + 4(-13)/11(3)
X= 7/3 -52/33 → (77-52)/33
So, X= 25/33
Hence the values of X and Y are 22/33 and -13/11 respectively...
Hopefully I was able to help you...
Have a great day ahead :)
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