Solve 4(2a + b)^2-(a - b)^2
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Answered by
0
Answer:
- 4(2a+b)^2-(a-b)^2
- 4(4a^2+b^2+4ab)-(a^2+b^2-2ab)
- 4(4a^2+b^2+4ab-a^2-b^2+2ab)
- 4(4a^2-a^2+b^2-b^2+4ab+2ab)
- 4(3a^2+6ab)
- 12a^2+24ab
Answered by
1
Answer:
We have
4(2a+b)² - (a-b)²
= 4(4a²+b²+4ab) - (a²+b²-2ab)
=16a² + 4b² + 16ab - a ²-b² + 2ab
=15a² + 3b² +18ab
=3(5a² + b² + 6ab)
=3(5a² + 6ab + b²)
=3(5a² +5ab + ab + b²)
=3{5a(a + b) + b(a + b)}
3(5a +b) (a +b)
I hope this will help you ☺️.
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