Question

Solve 4+ 6/y = 15 and
and 6x-8/y = 14 , find
a if y=ax-2​

Answer 1

Answer:

a=4/3

Step-by-step explanation:

The given system of the equation is,

$4x+\frac{6}{y}=15$------(1)

$6x-\frac{8}{y}=14$-------(2)

Multiplying equation (1) by 4 and equation (2) by 3,we get

$16x+\frac{24}{y}=60$-------(3)

$18x-\frac{24}{y}=42$-------(4)

Adding (4) and (3), we get,

$34x=102⇒x=3$

Putting x=3 in equation (1), we get

$12+\frac{6}{y}=15⇒y=2$

Hence, the solution of equations is x=3, y=2

Putting x=3, y=2 in y=ax-2,we get,

$2=3a-2⇒a=\frac{4}{3}$