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Let one number be x
Another becomes 7x
If 15 is added to both the numbers
=>(x+15)×5/2=(7x+15)
5 (x+15)=2 (7x+15)
5x+75=14x+30
14x-5x=75-30
9x=45
x=5
=>7x=7(5)=35
.°. The two numbers are 5,35
____________________________
HOPE IT HELPS !! ^^_^^
Another becomes 7x
If 15 is added to both the numbers
=>(x+15)×5/2=(7x+15)
5 (x+15)=2 (7x+15)
5x+75=14x+30
14x-5x=75-30
9x=45
x=5
=>7x=7(5)=35
.°. The two numbers are 5,35
____________________________
HOPE IT HELPS !! ^^_^^
Answered by
0
Hi ,
Let the first number = x
Second number = 7x
If 15 is added to the both numbers ,
New numbers are ,
First new number = x + 15
Second new number = 7x + 15
According to the problem given ,
(5/2 )( First new number) = ( second new number)
(5 /2 )(x + 15) = ( 7x + 15 )
5( x + 15 ) = 2( 7x + 15 )
5x + 75 = 14x + 30
75 - 30 = 14x - 5x
45 = 9x
45 / 9 = x
5 = x
Therefore ,
first number = x = 5
Second number = 7x
= 7 × 5
= 35
Required numbers are 5 and 35
I hope this helps you.
:)
Let the first number = x
Second number = 7x
If 15 is added to the both numbers ,
New numbers are ,
First new number = x + 15
Second new number = 7x + 15
According to the problem given ,
(5/2 )( First new number) = ( second new number)
(5 /2 )(x + 15) = ( 7x + 15 )
5( x + 15 ) = 2( 7x + 15 )
5x + 75 = 14x + 30
75 - 30 = 14x - 5x
45 = 9x
45 / 9 = x
5 = x
Therefore ,
first number = x = 5
Second number = 7x
= 7 × 5
= 35
Required numbers are 5 and 35
I hope this helps you.
:)
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