Math, asked by saumitrapatil29, 1 year ago

solve 4upon X +5upon Y = 7 ; 3upon X + 4 upon Y = 11 upon 2

Answers

Answered by 22072003
16
\dfrac{4}{X} + \dfrac{5}{Y} = 7

\dfrac{3}{X} + \dfrac{4}{Y} = \dfrac{11}{2}

Let,

\dfrac{1}{X} = x and \dfrac{1}{Y} = y

New equations –

4x + 5y = 7 _____( 1 )

3x + 4y = \dfrac{11}{2} ______( 2 )

Multiply ( 1 ) by 3, we get

12x + 15y = 21 _______( 3 )

Multiply ( 2 ) by 4, we get

12x + 16y = 22 ________( 4 )

Subtract ( 3 ) and ( 4 ), we get

15y - 16y = 21 - 22

- y = - 1

y = 1

Put this value in ( 1 ), we get

4x + 5 ( 1 ) = 7

4x + 5 = 7

4x = 7 - 5

4x = 2

x = \dfrac{2}{4}

x = \dfrac{1}{2}

Now, As we assumed earlier

\dfrac{1}{X} = x

So,

\dfrac{1}{X} = \dfrac{1}{2}

X = 2

Also,

\dfrac{1}{Y} = y

\dfrac{1}{Y} = 1

Y = 1

Hence, <b>X = 2 and Y = 1</b>


saumitrapatil29: thanks for the answer
Answered by nehasajy
9

Answer:

Hope this helps you

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