Question

solve 5x+10y=35 , 2x-4y=28​

Answer 1

$\huge \mathbb \red{ANSWER}$

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$\bf \underline{Question}$

solve 5x+10y=35 , 2x-4y=28

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$\bf \underline{step \: by \: step \: explanation}$

$\rm{⟹5x + 10y = 35.........eq(1)}$

$\rm{⟹2x - 4y = 28 ........eq(2)}$

$\tt{now \: divide \: by \: 2}$

$\rm{⟹x + 2y = 14}$

$\rm{⟹x = 14y - 2y}$

then

$⟹\rm{5(14 - 2y) + 3y = 35}$

$\rm{⟹70 - 10y + 3y = 35}$

$\rm{⟹70 - 7y = 35}$

$\rm{⟹70 - 35 = 7y}$

$\rm{⟹35 = 7y}$

$\rm{⟹y = \frac{35}{7}}$

$\rm{⟹y = 5}$

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$\rm{⟹x = 14 - 2y}$

$\rm{⟹14 - 2(5)}$

$\rm{⟹x = 4}$

I hope it's help uh

Answer 2

solution:-

=> 5x + 10y = 35 ......eq(1)

=> 2x - 4y = 28 .......eq(2)

Divided by 5 in eq (1)

=> x + 2y = 7

=> x = 7 - 2y

putting the above value in equation (2)

=> 2x - 4y = 28

=> 2(7 - 2y) - 4y = 28

=> 14 - 4y - 4y = 28

=> 14 - 8y = 28

=> - 8y = 28 -14

=> -8y = 14

=> y = -14/8

or, y = -7/4

And,

=>x = 7 - 2y

=> x = 7 - 2(-7/4)

=> x = 7 +7/2

=> x = 21/2

Now,

verified the solutions,

on putting the value x and y in equation(1)

=> 5x +10y = 35

=> 5(21/2)+10(-7/4) = 35

=> 105/2 -35/2 = 35

=> 105-35/2= 35

=> 70/2 = 35

=> 35 = 35

L. H. S = R. H. S

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