solve:5x^2-2x-8=0,and give your answer correct to 2 decimal places
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Solving 5x2-2x-8 = 0 by the Quadratic Formula :
According to the Quadratic Formula, x , the solution for Ax2+Bx+C = 0 , where A, B and C are numbers, often called coefficients, is given by :
- B ± √ B2-4AC
x = ————————
2A
In our case, A = 5
B = -2
C = -8
Accordingly, B2 - 4AC =
4 - (-160) =
164
Applying the quadratic formula :
2 ± √ 164
x = —————
10
Yes! The prime factorization of 164 is
2•2•41
To be able to remove something from under the radical, there have to be 2 instances of it (because we are taking a square i.e. second root).
√ 164 = √ 2•2•41 =
± 2 • √ 41
√ 41 , rounded to 4 decimal digits, is 6.4031
So now we are looking at:
x = ( 2 ± 2 • 6.403 ) / 10
Two real solutions:
x =(2+√164)/10=(1+√ 41 )/5= 1.481
or:
x =(2-√164)/10=(1-√ 41 )/5= -1.081
Two solutions were found :
x =(2-√164)/10=(1-√ 41 )/5= -1.08
x =(2+√164)/10=(1+√ 41 )/5= 1.48
Hope it helps.
Please mark it as brainliest.
According to the Quadratic Formula, x , the solution for Ax2+Bx+C = 0 , where A, B and C are numbers, often called coefficients, is given by :
- B ± √ B2-4AC
x = ————————
2A
In our case, A = 5
B = -2
C = -8
Accordingly, B2 - 4AC =
4 - (-160) =
164
Applying the quadratic formula :
2 ± √ 164
x = —————
10
Yes! The prime factorization of 164 is
2•2•41
To be able to remove something from under the radical, there have to be 2 instances of it (because we are taking a square i.e. second root).
√ 164 = √ 2•2•41 =
± 2 • √ 41
√ 41 , rounded to 4 decimal digits, is 6.4031
So now we are looking at:
x = ( 2 ± 2 • 6.403 ) / 10
Two real solutions:
x =(2+√164)/10=(1+√ 41 )/5= 1.481
or:
x =(2-√164)/10=(1-√ 41 )/5= -1.081
Two solutions were found :
x =(2-√164)/10=(1-√ 41 )/5= -1.08
x =(2+√164)/10=(1+√ 41 )/5= 1.48
Hope it helps.
Please mark it as brainliest.
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