Question

Solve (√6-√2) whole square​

Answer 1

Answer:

(√6)^2+(√2)^2-2(√6)(√2)

6+2-4√3

8-4√3

or

4(2-√3)

Answer 2

Answer:

$( \sqrt{6} - \sqrt{2} ) {}^{2}$

Using,

$(a + b) {}^{2} = {a}^{2} + 2ab+ {b}^{2}$

We get,

${( \sqrt{6} )}^{2} + 2( \sqrt{6} )( \sqrt{2}) + {( \sqrt{2} })^{2}$

$6 + 2 \sqrt{12} + 2$

$8 + 2 \sqrt{12}$

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