Question

Solve abx^2 +(b^2 - ac) x-bc=0

Answer 1

i think it is not a perfect question

Answer 2

x = -b/a, c/b

Step-by-step explanation:

$abx^2+(b^2-ac)x-bc=0$

or, $abx^2+b^2x-acx-bc=0$

or, $bx(ax+b)-c(ax+b)=0$

or, $(ax+b)(bx-c)=0$

$\impies x=-\frac{b}{a}, x=\frac{c}{b}$

Hope this answer is helpful.

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