Question

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Q8. Derive
(a) Position - Time relation,
(b) Velocity - Time relation and
(c) Position - Velocity relation by graphical method.
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Answer 1

Answer:

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Explanation:

a- Consider the graph shown in the given attachment. Obviously, the total distance s travelled by the object in time t is given by are under v-t graph. Obviously, OABGC is a trapezium, whose area is (OA + BC/2) × OC. Therefore, this equation is the position velocity relation for uniformly accelerated motion

b- Draw a line parallel to x-axis DA from point, D from where object starts moving. Draw another line BA from point B parallel to y-axis which meets at E at y-axis. Above equation is the relation among initial velocity (u), final velocity (v), acceleration (a) and time (t). It is called first equation of motion.

c- Derive an equation for position-velocity relation (2as=v2−u2) by graphical method. Let the object is moving with uniform acceleration, a. Draw a line parallel to x-axis DA from point, D from where object starts moving. Draw another line BA from point B parallel to y-axis which meets at E at y-axis.

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Answer 2

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