Question

solve and give explanation also​

Answer 1

$\huge{\boxed{\sf{SOLUTION-}}}$

Let, The acceleration be 'a'

From the question we can write,

Initial velocity of tge train, u = 0

Final velocity is = 40kmph

We have to convert 40kmph to 40m/s. To do this conversion multiply 40kmph with 5/18 m/s

v = 40kmph

v = 40 × 5/18

v = 11.11 m/s

Time given = 10 mins

Convert it into seconds by multiplying with 60

T = (10 × 60) seconds

T = 600 seconds

Using the 1st equation of motion,

v = u + at

11.11 = 0 + a × 600

$a = \frac{11.11}{600}$

a = 0.0185 m/s^2

Hence, the required acceleration is 0.0185 m/s^2

Answer 2

u = 0

v= 40kmph

v = 40 × 5/18

v = 11.11 m/s

Time = 10 mins

T = 600 seconds

From the 1st equation of motion,

v = u + at

11.11 = 0 + a × 600

$a = \frac{11.11}{600}$

a = 0.0185 m/s^2

Hence, the required acceleration is 0.0185 m/s^2