Question

Solve by quadratic formula or completion of square

$19. \: (a + b) {}^{2} x {}^{2} + 8(a {}^{2} - b {}^{2} )x + \\ 16(a - b) {}^{2} = 0$
Ans:
$\frac{4(b - a)}{(b + a)}$

Standard:- 10

Content Quality Solution Required

❎ Don't Spamming ❎

Answer 1

Given Equation is (a + b)^2x^2 + 8(a^2 - b^2)x + 16(a - b)^2 = 0.


The answer is explained in the attachment.


Hope it helps!