Solve by substitution method 2x+3y=13 and 2x-3y=-5
Answers
Answered by
11
Hey !!!!
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2x+3y = 13 (i)
2x-3y = -5 (ii)
In Equation (ii),
2x-3y = -5
2x = -5+3y
x = -5+3y/2
Putting this Value in Eq (i),
2x+3y = 13
-5+3y+3y =13 {2x = -5+3y}
-5+6y =13
6y = 13+5
6y = 18
y = 18/6
y = 3
Now,
2x-3y = -5
2x - 3*3 = -5
2x - 9 = -5
2x = -5+9
2x = 4
x = 4/2
x = 2
Hence, Value of x = 2
Value of y = 3
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Thanks....!!!!
Hope This Helps....!!!
tiwaavi:
Wonderfull answer.
Answered by
7
2x + 3y =13
x = (13 - 3y)/2
==================
Putting the value of x in 2x - 3y = -5
2(13 - 3y)/2 - 3y = -5
13 - 3y - 3y = -5
-6y = -18
y = 3
Then, putting the value of y in 2x + 3y =13
2x + 3(3) = 13
2x + 9 = 13
2x = 4
x = 2
I hope this will help you
-by ABHAY
x = (13 - 3y)/2
==================
Putting the value of x in 2x - 3y = -5
2(13 - 3y)/2 - 3y = -5
13 - 3y - 3y = -5
-6y = -18
y = 3
Then, putting the value of y in 2x + 3y =13
2x + 3(3) = 13
2x + 9 = 13
2x = 4
x = 2
I hope this will help you
-by ABHAY
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