Math, asked by bhattneeru3p8nct6, 1 year ago

Solve by substitution method 2x+3y=13 and 2x-3y=-5

Answers

Answered by Anonymous
11

Hey !!!!


__________________________

2x+3y = 13           (i)

2x-3y = -5             (ii)

In Equation (ii),

2x-3y = -5

2x = -5+3y

x = -5+3y/2

Putting this Value in Eq (i),

2x+3y = 13

-5+3y+3y =13                    {2x = -5+3y}

-5+6y =13

6y = 13+5

6y = 18

y = 18/6

y = 3

Now, 

2x-3y = -5

2x - 3*3 = -5

2x - 9 = -5

2x = -5+9

2x = 4

x = 4/2

x = 2

Hence, Value of x = 2

Value of y = 3

____________________________________

Thanks....!!!!

Hope This Helps....!!!



tiwaavi: Wonderfull answer.
Anonymous: Thanks
Answered by abhi569
7
2x + 3y =13

x = (13 - 3y)/2

==================

Putting the value of x in 2x - 3y = -5

2(13 - 3y)/2 - 3y = -5

13 - 3y - 3y = -5

-6y = -18

y = 3

Then, putting the value of y in 2x + 3y =13

2x + 3(3) = 13

2x + 9 = 13

2x = 4

x = 2



I hope this will help you


-by ABHAY

tiwaavi: Good Answer.
abhi569: (-:
Similar questions