solve :dy/dx -2y/x=y4
Answers
Answered by
1
hi,
When a differential eq is in the form dydx=Ay+Bx+C
MARK ME AS AN BRAINLIEST THANKS
When a differential eq is in the form dydx=Ay+Bx+C
, I always solve it this way:
Assume y
is of the form mx + b where m and bare arbitrary constants. Then, following your example:
Re-write your equation as m=2(mx+b)+x(because y = mx + b and m is the slope of the line.) Rearrange it so it becomes x(function of m)+(constant)b. In your case, 0x+m=x(2m+1)+2b. This is like equating real and imaginary parts. Split the equation into parts so it becomes 0x+m=x(2m+1)+2b. I did this so that we can equate coefficients of x and solve for m, then equate the green parts and solve for b. In this case,2m+1=0 and m=2b.The solution is then, y=−12x−14.
HOPE IT HELPS YOU..MARK ME AS AN BRAINLIEST THANKS
Answered by
0
I think it might be -4y+xd
Similar questions