Solve each of the following by 'completion of square' as well as by using ' quadratic formula':
![1. \: \sqrt{3} x {}^{2} + 10x + 7 \sqrt{3} = 0 1. \: \sqrt{3} x {}^{2} + 10x + 7 \sqrt{3} = 0](https://tex.z-dn.net/?f=1.+%5C%3A++%5Csqrt%7B3%7D+x+%7B%7D%5E%7B2%7D++%2B+10x+%2B+7+%5Csqrt%7B3%7D++%3D+0)
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![\frac{ - 7 \sqrt{3} }{3} \: , \: \: - \sqrt{3} \frac{ - 7 \sqrt{3} }{3} \: , \: \: - \sqrt{3}](https://tex.z-dn.net/?f=+%5Cfrac%7B+-+7+%5Csqrt%7B3%7D+%7D%7B3%7D+%5C%3A+%2C++%5C%3A++%5C%3A++-++%5Csqrt%7B3%7D+)
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RishabhBansal:
plz don't solve if u don't know the method . the question needs to be solved by competing the square
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Hey user
Here is your answer
![\sqrt{3} {x}^{2} + 10x + 7 \sqrt{3} =0 \\ \\ \sqrt{3} {x}^{2} + 3x + 7x + 7 \sqrt{3} = 0 \\ \\ \sqrt{3} x(x + \sqrt{3} ) + 7(x + \sqrt{3} ) = 0 \\ \\ (x + \sqrt{3} )( \sqrt{3} x + 7) = 0 \\ \\ x + \sqrt{3} = 0 \: \: \: \: \: \: or \: \: \: \: \: \sqrt{3} x + 7 = 0 \\ \\ x = - \frac{7}{ \sqrt{3} } \: \: \: \: \: or \: \: \: \: \: x = - \sqrt{3} \sqrt{3} {x}^{2} + 10x + 7 \sqrt{3} =0 \\ \\ \sqrt{3} {x}^{2} + 3x + 7x + 7 \sqrt{3} = 0 \\ \\ \sqrt{3} x(x + \sqrt{3} ) + 7(x + \sqrt{3} ) = 0 \\ \\ (x + \sqrt{3} )( \sqrt{3} x + 7) = 0 \\ \\ x + \sqrt{3} = 0 \: \: \: \: \: \: or \: \: \: \: \: \sqrt{3} x + 7 = 0 \\ \\ x = - \frac{7}{ \sqrt{3} } \: \: \: \: \: or \: \: \: \: \: x = - \sqrt{3}](https://tex.z-dn.net/?f=+%5Csqrt%7B3%7D++%7Bx%7D%5E%7B2%7D++%2B+10x+%2B+7+%5Csqrt%7B3%7D++%3D0+%5C%5C++%5C%5C++%5Csqrt%7B3%7D++%7Bx%7D%5E%7B2%7D++%2B+3x+%2B+7x+%2B+7+%5Csqrt%7B3%7D++%3D+0+%5C%5C++%5C%5C++%5Csqrt%7B3%7D+x%28x+%2B++%5Csqrt%7B3%7D+%29+%2B+7%28x+%2B++%5Csqrt%7B3%7D+%29+%3D+0+%5C%5C++%5C%5C+%28x+%2B++%5Csqrt%7B3%7D+%29%28+%5Csqrt%7B3%7D+x+%2B+7%29+%3D+0+%5C%5C++%5C%5C+x+%2B++%5Csqrt%7B3%7D++%3D+0+%5C%3A++%5C%3A++%5C%3A++%5C%3A++%5C%3A++%5C%3A+or+%5C%3A++%5C%3A++%5C%3A++%5C%3A++%5C%3A++%5Csqrt%7B3%7D+x+%2B+7+%3D+0+%5C%5C++%5C%5C+x+%3D+++-+%5Cfrac%7B7%7D%7B+%5Csqrt%7B3%7D+%7D++%5C%3A++%5C%3A++%5C%3A++%5C%3A++%5C%3A+or+%5C%3A++%5C%3A++%5C%3A++%5C%3A++%5C%3A+x+%3D++-++%5Csqrt%7B3%7D+)
Thank you.
Here is your answer
Thank you.
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