Solve each of the following systems of equations by the method of cross-multiplication:
6(ax+by)=3a+2b6(bx-ay)=3b-2a
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Given:
6(ax+by)= 3a+2b
6(bx -ay)=3b-2a
To find:
Solution to the equations
Answer:
1.Solve each of the following system of equations by the method of cross- multiplication.
2.Equations are
6(ax+by)= 3a+2b
6(bx -ay)=3b-2a
3 .By rearranging these equations we get,
6ax +6b y-(3a+2b)=0
6bx-6a y -(3b-2a) =0
4 .By cross multiplication method we get values as,
x = 1/2, y =1/3
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