Question

solve following simultaneous equation 1/x+1/y=12 ; 3/x-2/y=1​

Answer 1

x=1/5

y=1/7

hope it helps u

Answer 2

Answer:

$[x = \frac{1}{5} \: and \: y = \frac{1}{7}] .$]

Step-by-step explanation:

$\frac{1}{x} + \frac{1}{y} = 12 \: \: ......eq1$

$\frac{3}{x} - \frac{2}{y} = 1 \: \: \: \: ......eq2$

$let \: \frac{1}{x} \: be \: u. \\ \: \: \: \: \: \: \\ \: \: \: \: \: \: \frac{1}{y} \: be \: v.$

Then,

$u + v = 12 \: \: \: \: .......eq3$

$3u - 2v = 1 \: \: .......eq4$

Now on further solving eq 3 & eq 4, we get

$= > u + v = 12 \\ = > v = 12 - u$

On Putting this value in eq 4,

$= > 3u - 2(12 - u) = 1 \\ = > 3u - 24 + 2u = 1 \\ = > 5u = 25 \\ = > u = 5$

$Thus \: if \: \: u =5 \: \\ then \: \: v=(12-5)=7$

$as \: \frac{1}{x} = u \\ =>\frac{1}{x} = 5 \\=> x = \frac{1}{5}$

And,

$as \: \frac{1}{y} = v \\ =>\frac{1}{y} = 7 \\=> y = \frac{1}{7}$