Math, asked by mrgaaj, 9 months ago

Solve for 50 points.. Calculus class 11​

Attachments:

Answers

Answered by Anonymous
1

heya mate

answer will be

Hey mate!!!!

lim (x→0) [ sin ( π cos² x ) ] / x²  

= lim (x→0) { sin [ π ( 1 - sin² x ) ] } / x²  

= lim (x→0) [ sin ( π - π sin² x ) ] / x²  

= lim (x→0) [ sin ( π sin² x ) / x²  

= lim (x→0) [ ( π sin² x ) / x² ] ....................... from (1)  

= π • [ lim (x→0) ( (sin x) / x ) ]²  

= π • [ 1 ]²  

= π ........................................... Ans.

Ans---- Option b

Answered by devanayan2005
1

Hey mate!!!!

lim (x→0) [ sin ( π cos² x ) ] / x²  

= lim (x→0) { sin [ π ( 1 - sin² x ) ] } / x²  

= lim (x→0) [ sin ( π - π sin² x ) ] / x²  

= lim (x→0) [ sin ( π sin² x ) / x²  

= lim (x→0) [ ( π sin² x ) / x² ] ....................... from (1)  

= π • [ lim (x→0) ( (sin x) / x ) ]²  

= π • [ 1 ]²  

= π ........................................... Ans.

Ans------- Option b

Hope it helps you

Similar questions