Question

Solve for the following logarithmic functions: (a) log3 (2x-1) = 2 x = Answer (b) logx 16 = 2 x =

Answer 1

1. Given,  log3 (2x-1) = 2  

It can be written as  2x - 1 = 3^2 

                                2x = 9 + 1

                                 x = 5.


2. Given, logx 16 = 2  

It can be written as   16 = x^2

                                   x = 4.



                                            Hope this helps.