CBSE BOARD X, asked by tanlann, 1 year ago

Solve for the following system of linear equations. Please help !!

3(bx + ay) = a - 6b
3(ax - by) = - (6a + b)

Answers

Answered by 16Devesh16
13
hope it helps you.....
Attachments:
Answered by Anonymous
13
Hey friend!!


Here's ur answer...


==========================

3bx + 3ay = a - 6b -------------(1)


3ax - 3by = - 6a - b ---------------(2)


Multiply (1) by a and (2) by b and subtract

3abx + 3a²y = a² - 6ab
3abx - 3b²y = - 6ab - b²
Subtracting
_____________________

0 + 3a²y + 3b²y = a² + b²
3y (a²+ b²) = a ² + b²
3y = 1

y = 1/3

Put in (1)

3bx + 3a (1/3) = a - 6b
3bx + a = a - 6b
3bx + 6b = 0
3b (x +2) = 0
x + 2 = 0

x = - 2




==============================




Hope it may help you....



Thank you :) :)))


Similar questions