Solve for the following system of linear equations. Please help !!
3(bx + ay) = a - 6b
3(ax - by) = - (6a + b)
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hope it helps you.....
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Answered by
13
Hey friend!!
Here's ur answer...
==========================
3bx + 3ay = a - 6b -------------(1)
3ax - 3by = - 6a - b ---------------(2)
Multiply (1) by a and (2) by b and subtract
3abx + 3a²y = a² - 6ab
3abx - 3b²y = - 6ab - b²
Subtracting
_____________________
0 + 3a²y + 3b²y = a² + b²
3y (a²+ b²) = a ² + b²
3y = 1
y = 1/3
Put in (1)
3bx + 3a (1/3) = a - 6b
3bx + a = a - 6b
3bx + 6b = 0
3b (x +2) = 0
x + 2 = 0
x = - 2
==============================
Hope it may help you....
Thank you :) :)))
Here's ur answer...
==========================
3bx + 3ay = a - 6b -------------(1)
3ax - 3by = - 6a - b ---------------(2)
Multiply (1) by a and (2) by b and subtract
3abx + 3a²y = a² - 6ab
3abx - 3b²y = - 6ab - b²
Subtracting
_____________________
0 + 3a²y + 3b²y = a² + b²
3y (a²+ b²) = a ² + b²
3y = 1
y = 1/3
Put in (1)
3bx + 3a (1/3) = a - 6b
3bx + a = a - 6b
3bx + 6b = 0
3b (x +2) = 0
x + 2 = 0
x = - 2
==============================
Hope it may help you....
Thank you :) :)))
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