solve for x............................
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Solution
Given :-
- 1/x + 1/y = 6 -----------Equ(1)
- 1/y + 1/z = 7 ----------Equ(2)
- 1/z + 1/x = 5-----------Equ(3)
Find :-
- Value of x ,y % z
Explanation
Add equ(1) , equ(2) & equ(3)
we get , here
==> (1/x + 1/y) + (1/y + 1/z) + (1/z + 1/x) = 6 + 7 + 5
==> 2( 1/x + 1/y + 1/z) = 18
==> ( 1/x + 1/y + 1/z) =18/2
==> ( 1/x + 1/y + 1/z) = 9 -----------Equ(4)
First, Keep Value by equ(1) .
==> ( 6 + 1/z) = 9
==> 1/z = 9 - 6
==> 1/z = 3
==> z = 1/3
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Second ,keep value by equ(2)
===> (1/x + 7 ) = 9
==> 1/x = 9 - 7
==> 1/x = 2
==> x = 1/2
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Third , keep value by equ(3)
==> (1/y + 5) = 9
==> 1/y = 9 - 5
==> 1/y = 4
==> y = 1/4
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Hence
- Value of x = 1/2
- Value of y = 1/4
- Value of z = 1/3
Ans.
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Answered by
2
Answer:
x=1/2
Step-by-step explanation:
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