Math, asked by vijayyadavvy26796, 8 months ago

solve for x............................​

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Answers

Answered by Anonymous
7

Solution

Given :-

  • 1/x + 1/y = 6 -----------Equ(1)
  • 1/y + 1/z = 7 ----------Equ(2)
  • 1/z + 1/x = 5-----------Equ(3)

Find :-

  • Value of x ,y % z

Explanation

Add equ(1) , equ(2) & equ(3)

we get , here

==> (1/x + 1/y) + (1/y + 1/z) + (1/z + 1/x) = 6 + 7 + 5

==> 2( 1/x + 1/y + 1/z) = 18

==> ( 1/x + 1/y + 1/z) =18/2

==> ( 1/x + 1/y + 1/z) = 9 -----------Equ(4)

First, Keep Value by equ(1) .

==> ( 6 + 1/z) = 9

==> 1/z = 9 - 6

==> 1/z = 3

==> z = 1/3

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Second ,keep value by equ(2)

===> (1/x + 7 ) = 9

==> 1/x = 9 - 7

==> 1/x = 2

==> x = 1/2

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Third , keep value by equ(3)

==> (1/y + 5) = 9

==> 1/y = 9 - 5

==> 1/y = 4

==> y = 1/4

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Hence

  • Value of x = 1/2
  • Value of y = 1/4
  • Value of z = 1/3

Ans.

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Answered by ramlaxman24
2

Answer:

x=1/2

Step-by-step explanation:

HOPE IT'S HELPFUL..

THANK you..

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