solve for x
3^2x - 12(3^x) + 27 = 0
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3^2x-12(3^x)+27=0
9x×x×x-12×x×x×x+27=0
9x×x×x-12×x×x×x=-27
-3×x×x×x=-27
x×x×x=-27/-3
x×x×x=9
x=
![\sqrt[3]{9}](https://tex.z-dn.net/?f=+%5Csqrt%5B3%5D%7B9%7D+ "\sqrt[3]{9}")
x=2.08
9x×x×x-12×x×x×x+27=0
9x×x×x-12×x×x×x=-27
-3×x×x×x=-27
x×x×x=-27/-3
x×x×x=9
x=
x=2.08
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