solve for x (4x-3/2x+1)-10*(2x+1/4x-3)=3
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Hi there!
Let 4x-3/2x+1 = x
& 2x+1/4x-3 =1/x [Since it's reciprocal]
So,
x - 10(1/x) = 3
x - 10/x = 3
x²- 10 = 3x
x² - 3x - 10 = 0
x² - 5x + 2x - 10 = 0
x (x - 5) + 2(x - 5) = 0
(x - 5)(x + 2) = 0
x = 5 and x= -2
Cheers!
Let 4x-3/2x+1 = x
& 2x+1/4x-3 =1/x [Since it's reciprocal]
So,
x - 10(1/x) = 3
x - 10/x = 3
x²- 10 = 3x
x² - 3x - 10 = 0
x² - 5x + 2x - 10 = 0
x (x - 5) + 2(x - 5) = 0
(x - 5)(x + 2) = 0
x = 5 and x= -2
Cheers!
rashi46:
I think it is a wrong method
Maths has different ways to solve any question... It's an Alternative one
It's Correct :)
I know
okk fine
may it be possible that I am not aware about this method
:)
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I hope you understand this answer
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