Question

Solve for x and y (a^2x+b^2y=c^2 ; b^2x+a^2y=d^2 )

Answer 1

Step-by-step explanation:

Given Equations are,

a²x + b²y - c² = 0   ---- (1)

b²x + a²y - d² = 0   ----- (2)

Here,

a₁ = a, b₁ = b², c₁ = -c²

a₂ = b, b₂ = a², c₂ = -d²

By cross-multiplication, we have

=> (x/-b²d² + a²c²) = (-y/-a²d² + b²c²) = 1/a⁴ - b⁴

Now,

(x/-b²d² + a²c²) = (1/a⁴ - b⁴)

x = (a²c² - b²d²/a⁴ - b⁴)

and,

(-y/-a²d² + b²c²) = 1/a⁴ - b⁴

y = (a²d² - b²c²)/a⁴ - b⁴

Therefore,

x = (a²c² - b²d²/a⁴ - b⁴)

y = (a²d² - b²c²/a⁴ - b⁴)

Hope it helps!

Answer 2

Answer:

already answered so i wanted points to ask answer

Step-by-step explanation:

hope u dont mind