Math, asked by sandeepsharan2258, 1 year ago

Two positive integers A and B satisfy A/11 + 7/33 = 7/33. Maximum of the value of

Answers

Answered by Dipakchandpa
2
max value of what???
Answered by deepakbalum
0

Answer:

A^2+B^2=5

Step-by-step explanation:

A/11+B/3=17/33

3A+11B/33=17/33

3A+11B=17

A=2,B=1

OR

A=13, B=-2

(Ao,Bo)=(13,-2)

A=13+11y

B= -2-3t

wher t belongs to integers

A>OR EQUAL TO 1

T BELONGS TO [-1, infinity)

B> or equal to 1,

T belongs to (-INFINITY,-1]

t=-1

A=2

B=1

So A^2+b^2=5

please mark me as brainalest

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