Two positive integers A and B satisfy A/11 + 7/33 = 7/33. Maximum of the value of
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max value of what???
Answered by
0
Answer:
A^2+B^2=5
Step-by-step explanation:
A/11+B/3=17/33
3A+11B/33=17/33
3A+11B=17
A=2,B=1
OR
A=13, B=-2
(Ao,Bo)=(13,-2)
A=13+11y
B= -2-3t
wher t belongs to integers
A>OR EQUAL TO 1
T BELONGS TO [-1, infinity)
B> or equal to 1,
T belongs to (-INFINITY,-1]
t=-1
A=2
B=1
So A^2+b^2=5
please mark me as brainalest
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