Question

solve for x and y: x-y=3,x/3+y/2=6

Answer 1

Heya!!,

it can be done with any method but the answer remains same
i m doing with SUBSTITUTION method 

By substitution method
x-y=3=> x=y+3
x/3+y/2=6
Substituting in (x/3+y/2=6)
=>(y+3)/3+y/2=6
=>(2y+6+3y)/6=6
=>2y+6+3y=36
=>5y=30
=>y=5

Substituting (y= 5)in x-y=3
we get x=8


ANS:- x=8,,,,,y=5


THANK YOU 

hope this helps!!!!

Answer 2

Solution:

$\frac{x}{3} + \frac{y}{2} = 6 \\ \frac{2x + 3y}{6} = 6 \\ 2x + 3y = 6 \times 6 \\ 2x + 3y = 36⟹⓵ \\ \\ (x - y = 3) \times 2 \\ 2x - 2y = 6⟹⓶ \\ \\ 2x + 3y = 36 \\ 2x - 2y = 6 \\ ( - ) \: \: ( - ) \: \: ( - ) \\ - - - - - - - \\ 5y = 30 \\ y = \frac{30}{5} \\ \boxed{ \large y = \underline{ \underline{ 6}}} \\ \\ 2x + 3y = 36 \\ 2x + 3(6) = 36 \\ 2x + 18 = 36 \\ 2x = 36 - 18 \\ 2x = 18 \\ x = \frac{18}{2} \\ \boxed{ \large x = \underline{ \underline{ 9}}}$