Question

Solve for x, log(x + 1) -1 = 3 + log, (x - 1)​

Answer 1

answer to the question is

Answer 2

Answer:

$= > log(x + 1) - 1 = 3 + log(x - 1) \\ \\ = > log(x + 1) - log(x - 1) = 4 \\ \\ \: but \: \: \: \: \: log(m) - log(n) = log( \frac{m}{n} ) \\ \\ = > log( \frac{x + 1}{x - 1} ) = 4 \\ \\ = > \frac{x + 1}{x - 1} = {10}^{4} \\ \\ = > x = \frac{ {10}^{4} + 1}{ {10}^{4} - 1}$