Solve for x: x 2 -(2b- 1)x + (b2 -b-20) = 0
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LHS = Using C 1 → C 1 + C2 + C3, 3x +3y x + y x + 2y = 3x +3y x x + y 3x +3y x + 2y x ... C1 and C2, 1 0 −2b = (1+a2 + b2) 2 0 1 2a b −a 1 −a2 − b2 Using R3 → R3 + aR2 –bR1, 1 0 ...
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