Solve
i)2x-(4-x)=5-x
ii)(x+3÷7)-(x-2÷9)=8
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(1) 2x-4+x=5-x
then,
x=9/4
then,
x=9/4
priyankomanna:
(2) x=463/2
Can you explain the process
just simplify.
Answered by
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i) 2x-(4-x)=5-x
=2x-4+x=5-x
3x-4=5-x
4x=9
x=9/4
i) (x+3)/7-(x-2)/9=8
[9x+27-(7x-14)]/63=8
9x+27-7x+14=63×8
2x+41=508
2x=508-41
2x=467
x=467/2
x=233.5
hope it's useful for you
please give me a brainlist
=2x-4+x=5-x
3x-4=5-x
4x=9
x=9/4
i) (x+3)/7-(x-2)/9=8
[9x+27-(7x-14)]/63=8
9x+27-7x+14=63×8
2x+41=508
2x=508-41
2x=467
x=467/2
x=233.5
hope it's useful for you
please give me a brainlist
It is 4-x not 4+x
the minus sign in outside of bracket so it wii be changed inner sign while '-' to '+' or '+' to '-'
63×8=504 not 508
please check l think lt will hlep you.
sorry it will my mistake
I am solving by 504
2x=504-41
x=463
not 2x=463
x=463/2=231.5
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