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1 g of the compound has .75g of C or .75/12 moles of C = 0.0625
1 g of the compound has .25g of H or .25/1 moles of H = 0.25
molar ratio C : H = .0625 : .25 = 1 : 4
empirical formula is CH4 ..
1 g of the compound has .25g of H or .25/1 moles of H = 0.25
molar ratio C : H = .0625 : .25 = 1 : 4
empirical formula is CH4 ..
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