Math, asked by abcdef62554, 9 months ago

solve it plz its of maths ​

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Answers

Answered by srujana40
0

Answer:

y=4/5

X=7/4

Step-by-step explanation:

assume( 1/x-1) as A and (1/y-1) as B

then the equations are

4A+5B=2 --(1)

8A+15B=3 --(2)

multiply 1st equation with 2

2(4A+5B)=2(2)

8A+10B=4 --(3)

solve 3 and 2 then we will get y=4/5

next multiply equation 1 with 3

3(4A+5B)=3(2)

12A+15B=6 --(4)

by solving equation 4 and 2 then we will get X=7/4

Answered by tahseen619
1

x = 7/3 and y = -4.

Step-by-step explanation:

Given:

  \frac{4}{x - 1}  +  \frac{5}{y - 1}   = 2   \:  ---(a) \\  \\\frac{8}{x - 1}  +  \frac{15}{y - 1} = 3 \:---(b)

To find:

Find the value of x and y

Solution:

I will use the elimination method to solve this equation.

What is Elimination method ?

(See in attachment)

________________________________

Multiplying (a) by 2,

  2 (\frac{4}{x - 1}  +  \frac{5}{y - 1}) = 2 ( 2 ) \\  \\\frac{8}{x - 1}  +  \frac{10}{y - 1} = 4

Now, Subtracting (a) from (b)

 (\frac{8}{x - 1}  +  \frac{15}{y - 1})  - ( \frac{8}{x - 1}  +  \frac{10}{y - 1} )= 3 - 4\\  \\ \cancel{\frac{8}{x - 1}}  +  \frac{15}{y - 1}  -  \cancel{\frac{8}{x - 1}}  -  \frac{10}{y - 1} =  - 1 \\  \\ \frac{15 - 10}{y - 1} =  - 1 \\  \\   [\text{by cross multiple}] \\  \\ 5 =  - 1(y - 1) \\  \\ 5 =  - y  + 1 \\  \\ y = 1 - 5 \\  \\ y =  - 4

Now, putting the value of y in (a),

 \frac{4}{x - 1}  +  \frac{5}{y - 1}   = 2    \\  \\  \frac{4}{x - 1} +  \frac{5}{ - 4 - 1}   = 2 \\  \\  \frac{4}{x - 1} + \frac{5}{ - 5}  = 2 \\  \\  \frac{4}{x - 1} - 1 = 2 \\  \\  \frac{4}{x - 1}     = 2 + 1 \\  \\  [\text{by cross multiple}] \\  \\  \frac{4}{3} = x - 1 \\  \\  \frac{4}{3}    + 1 = x \\  \\ x =  \frac{7}{3}

Therefore, the required value of x = 7/3 and y = -4.

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