Question

Solve it , step by step​

Answer 1

angle aeo + angle afo = 180

quad. afoe is cyclic

angle feo = angle fao (angles inscirbed in same arc)

angles aeb and adb are 90°

a,b,d and e are concyclic

angle bed=angle bad (angles inscribed in same arc)

angle oed = angle fao (b-f-a, a-o-d)

angle feo is equal to angle oed

ray eo bisects angle fed

similarly, fo and do r angle bisectors

o is their point of intersection

hence, 0 is the incentre of ∆DEF..