Math, asked by suvro9, 11 months ago

solve it......very simple.....

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suvro9: 1 min
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Answers

Answered by adee1729
2
sec17°/cosec(90°-17°) + tan68°/cot(90°-68°) + cos²(90°-46°) + cos²46°,


sec17°/sec17° + tan68°/tan68° + sin²46° + cos²46°,

1 + 1 + (sin²46°+cos²46°),

2 + 1,

3


suvro9: nice
Answered by Anonymous
1
=sec (90-73^)/cosec 73+ tan68/cot(90-68)+cos^2(90-46)+cos^2 46
=cosec73/cosec73+tan68/tan68+sin^2 46+cos^2 46
=1+1+1=3

suvro9: nice
Anonymous: thnx
alexbrainly: Hi richa
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