solve no 13 ..... please.
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1st
distance =speed*time
=25*5
=125 m
2nd
v=u +at
0=25+a*10
a=-25/10
=-2.5
3rd
s=ut+1/2at^2
s=25*10+1/2*(-2.5)*10^2
s=250-250/2
s=125m
or
v^2=u^2+2as
0=25^2+2*-2.5*s
625=5s
s=125
distance =speed*time
=25*5
=125 m
2nd
v=u +at
0=25+a*10
a=-25/10
=-2.5
3rd
s=ut+1/2at^2
s=25*10+1/2*(-2.5)*10^2
s=250-250/2
s=125m
or
v^2=u^2+2as
0=25^2+2*-2.5*s
625=5s
s=125
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