Question

solve pls i need real help for this​

Answer 1

Answer:

Proved: $\frac{x^{a(b-c)}}{x^{b(a-c)}} \div [\frac{x^{b}}{x^{a}}]^{c}=1$

Step-by-step explanation:

The expression is:

$\frac{x^{a(b-c)}}{x^{b(a-c)}} \div [\frac{x^{b}}{x^{a}}]^{c}$

Solve the expression as follows:

$\frac{x^{a(b-c)}}{x^{b(a-c)}} \div [\frac{x^{b}}{x^{a}}]^{c}=\frac{x^{ab-ac}}{x^{ba-bc}} \div [\frac{x^{bc}}{x^{ac}}]=x^{ab-ac-ba+bc}\div x^{bx-ac}=x^{bx-ac}\div x^{bx-ac}=1$

Hence proved.