solve plzz.... trigonometry
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cos 3theta = 4 cos^3 theta - 3 cos theta
LHS = Cos 3theta = Cos 90°
= 0
RHS = 4cos³30° - 3cos30°
= 4 (√3/2)³ - 3√3/2
= 4*3√3/8 - 3√3/2
= 3√3/2 - 3√3/2
= 0
Clearly, LHS = RHS = 0
LHS = Cos 3theta = Cos 90°
= 0
RHS = 4cos³30° - 3cos30°
= 4 (√3/2)³ - 3√3/2
= 4*3√3/8 - 3√3/2
= 3√3/2 - 3√3/2
= 0
Clearly, LHS = RHS = 0
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