Question

solve Q. 9 10 and 11.plzzz

Answer 1

here the answer of 10

Answer 2

9.Let the no. coins of denomination Rs. 1 is x
So the no. of coins of denomination Rs. 2 is 3 times of Rs. 1. Hence it is 3x.
Again the no. of coins of denomination Rs. 5 are twice the no. of Rs. 2.
So,the no. of coins of denomination Rs. 5 are 2× 3x=6x
According to the question Manav has 740 rupees.

Hence, x ×1+3x ×2+6x ×5=740
37x=740
So,x=740/37
x=20
Hence,no. Of coins of denomination Rs. 1 is x=20
No. of coins of denomination Rs. 2 is 3x=3×20=60
No. of coins of denomination Rs. 5 is 6x i. e 6×20=120
10.Let Sonika had Rs. x
So, x/2+(1/2×x/2)+(1/2×x/4)+20=x
x/2+x/4+x/8+20=x
7x/8=x-20
7x=8(x-20)
7x=8x-160
8x-7x=160
x=160
Hence,Sonika had taken Rs. 160 for shopping.