Question

solve question in above pic​

Answer 1

$\huge\underline\orange{\mathcal Answer}$

$\large\blue{\boxed{\mathcal Max\:Kinetic\:Energy(KE)=18J}}$

$\huge\orange{\mathcal Solution}$

From Work Energy Theorem :-

$\huge{\boxed{\mathcal KE={\int{\limits^t_t(F)dx}}}}$

$\large{\mathcal KE={\int{\limits^x_0(9-{x}^{2})}}}$

$\large{\mathcal KE=9x-{\frac{{x}^{3}}{3}}}$

For maximum Kinetic Energy $\large{\mathcal {\frac{dK}{dx}=0}}$

$\large{\mathcal {\frac{dK}{dx}}=9-{x}^{2}}$

$\large{\mathcal 9={x}^{2}}$

x=3

For Maximum kinetic energy

$\large{\mathcal Kmax=9(3)-{\frac{{3}^(3}}{3}}}$

$\large{\mathcal Kmax={\frac{54}{3}}}$

$\huge{\boxed{\mathcal Kmax=18J}}$

$\huge\orange{\mathcal Hope\:It\:Helps!!!}$