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Solution :-
Dimensions of a room = 8m , 5m , 6 m
Thus ,
Lateral surface of walls = 2(L+B)H
=2(8m+6m) * 5m
= 2*14m*5m
=140m^2
Now ,
Cost of distempering it's walls =
Rs . ( 140 * 80)
= Rs. 11, 200
Ans . Rs . 11,200 is the cost of distempering it's walls .
Dimensions of a room = 8m , 5m , 6 m
Thus ,
Lateral surface of walls = 2(L+B)H
=2(8m+6m) * 5m
= 2*14m*5m
=140m^2
Now ,
Cost of distempering it's walls =
Rs . ( 140 * 80)
= Rs. 11, 200
Ans . Rs . 11,200 is the cost of distempering it's walls .
akshisaha06:
Hope my answer helps !!!
Answered by
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length=8
breath=6m
height=5m
cost of distempering of its four wall at the rate of 80 per m^2 is
2h(l+b)
=2x5(8+6)
=10(14)
=140m^2
cost of distempering is 140x80= Rs 11,200
breath=6m
height=5m
cost of distempering of its four wall at the rate of 80 per m^2 is
2h(l+b)
=2x5(8+6)
=10(14)
=140m^2
cost of distempering is 140x80= Rs 11,200
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