Math, asked by moora, 11 months ago

solve root x^2-16-root x^2-8x+16=root x^2-5x+4

Answers

Answered by rishika79
6

Answer:

hope this is true and helpful to you

Attachments:

KumarJayant: please check in 4th row of solution
rishika79: you can report it
KumarJayant: yes i had reported it
KumarJayant: x^2-5x-4
KumarJayant: will be equation
KumarJayant: check yourself
rishika79: ok thanks
KumarJayant: u agreed with me or not..
rishika79: yssa
KumarJayant: hope so!
Answered by KumarJayant
15

Answer:

Hello mate,

taking square both sides of original eqn, we get:

x^2-16-root (x^2-8x+16)=x^2-5x+4

or, -root (x^2-8x+16)=-5x+20

or, root (x^2-8x+16)=5x-20

or, x^2-8x+16=25x^2+400-200x

or, 24x^2-192x+384=0

or, x^2-8x+16=0

or, x^2-4x-4x+16=0

or, (x-4)^2=0

i.e, x-4=0

so, x=4 will be answer...

hope it will help u...

please mark as brainliest...

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