solve root x^2-16-root x^2-8x+16=root x^2-5x+4
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Answered by
6
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KumarJayant:
please check in 4th row of solution
Answered by
15
Answer:
Hello mate,
taking square both sides of original eqn, we get:
x^2-16-root (x^2-8x+16)=x^2-5x+4
or, -root (x^2-8x+16)=-5x+20
or, root (x^2-8x+16)=5x-20
or, x^2-8x+16=25x^2+400-200x
or, 24x^2-192x+384=0
or, x^2-8x+16=0
or, x^2-4x-4x+16=0
or, (x-4)^2=0
i.e, x-4=0
so, x=4 will be answer...
hope it will help u...
please mark as brainliest...
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