Question

solve that Q..........

Answer 1

We have, wn = V²/R =at² or v= √aRt,
t is defined to start from the beginning of motion from rest.
So, Wt =dv/dt = √aR
Instantaneous power, p= F.v = m(Wt Ut + Wn Ut) .(√aRt Ut),
[where Ut and Ut are Unit vectors along the direction of tangent (velocity) and normal respectively]

Then the continues is in the picture.

Hope this helps you friend
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