Solve the attached problem.
Explanation is necessary !!
Content Quality Answer Needed !!
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Answers
Solution:-
Case l —
There are three headphones.
→ 1 headp. + 1 headp. + 1 headp. = 30
→ 3 headphones = 30
→ 1 headphone = 30/3
→ 1 headphone = 10 ------- Equation (1)
Case 2 —
There are 1 headphone, 2 speakers.
→ 1 headp. + 1 speaker + 1 speaker = 18
→ 10 + 2 speakers = 18
→ 2 speakers = 18 - 10
→ 2 speakers = 8
→ 1 speaker = 8/2
→ 1 speaker = 4 ------- Equation (2)
Case 3 —
There are 1 speaker & 1 locket.
→ 1 speaker - 1 locket = 2
→ 4 - 1 locket = 2
→ 4 - 2 = 1 locket
→ 1 locket = 2 ------- Equation (3)
Case 4 — (Last one!)
There are 1 speaker, 1 locket & 1 headphone.
Putting values from (Eq.1) , (Eq.2) & (Eq.3)
→ 1 speaker + 1 locket + 1 headp. = ??
→ 4 + 2 + 10 = ??
→ 16 = ??
→ 16
Therefore,
Your required answer is 16 .
☯ AnSwEr :
★ Case 1 :
Let the headphones in case 1 be x.
So,
x + x + x = 30
→ 3x = 30
→x = 30/3
→x = 10 ......(1)
1 headphone is equal to the 10.
★ Case 2 :
Let the speakers be y.
So,
→x + y + y = 18
→ 10 + 2y = 18
→ 2y = 18 - 10
→2y = 8
→y = 8/2
→ y = 4 ......(2)
1 speaker is equal to the 4.
★ Case 3 :
Let the locket be z.
So,
→ y - z = 2
→ 4 - z = 2
→-z = 2 - 4
→z = 2 .......(3)
1 locket is equal to the 2.
★ Case 4 :
↪From equation (1), (2) and (3).
→x + y + z = ??
→2 + 4 + 10 = ??
→ ?? = 16
16 is the required answer.