solve the equation 8x-3/3x=2
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First of all you needn't have to post picture of yours!
» 8x-3/3x = 2
» 24x² - 3 = 6x
» 24x² - 6x - 3 = 0
» 3(8x² - 2x - 1 ) = 0
» 8x² - 2x - 1 = 0
» 8x² - ( 4 - 2 ) x - 1 = 0
» 8x² - 4x + 2x - 1 = 0
» 4x ( 2x - 1 ) + 1( 2x - 1 )= 0
» ( 2x - 1 ) ( 4x + 1 ) = 0
_______________________________
» 8x-3/3x = 2
» 24x² - 3 = 6x
» 24x² - 6x - 3 = 0
» 3(8x² - 2x - 1 ) = 0
» 8x² - 2x - 1 = 0
» 8x² - ( 4 - 2 ) x - 1 = 0
» 8x² - 4x + 2x - 1 = 0
» 4x ( 2x - 1 ) + 1( 2x - 1 )= 0
» ( 2x - 1 ) ( 4x + 1 ) = 0
_______________________________
Answered by
0
The ans is given in this
capture
From 5 line
4x(2x-1) 1(2x-1) =0
(2x-1) (4x+1) =0
x=1/2, -1/4
capture
From 5 line
4x(2x-1) 1(2x-1) =0
(2x-1) (4x+1) =0
x=1/2, -1/4
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prabhash0101:
Sry for the mistake
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