Question

solve the equation and send a pic to answer

Answer 1

Hello zico!!
the answer will not be 4..
please check it again or it might be a mistake for sure...

please follow the photo to get the answer for your query...

hope this helps!!! cheers!! (:

Answer 2

Answer:

--> We try at f ( 2 ) to get f(x) = 0 at x = 2 ;

=> f(x) = ( x - 2 )( 12x³ - 32x² + 25x - 6 )

Now, We try at --> x = 2 ; x = 3 and x = 1 , x = 0 , x = -1

We see that the roots are non-negative....

By real root theorem, we have p = 12 , q = -6

One possible root = 6/12 = 1/2

So, we try at 6/12 ---> f(x) = 0

Hence, ( 2x - 1 ) is also a factor

=> f ( x ) = ( x - 2 )( 2x - 1 )( 6x² - 13x + 6 )

=> f ( x ) = ( x - 2 )( 2x - 1 )( 3x - 2 )( 2x - 3 ) √√

Now, for the roots, we have -->

-----> f ( x ) = 0

=> x = 2 || x = 1/2 ||| x = 2/3 |||| x = 3/2 = 1.5 √√

☆☆ Hope this helps you ☆☆