Math, asked by vedehi32, 1 year ago

solve the equation b^4-3b^2+28

Answers

Answered by vaibhavanand108

1

Answer:

b^4-3b^2+28

(b^2)^2 -2×(3/2)×b^2 +(9/4) +103/4

(b^2-(3/2))^2 +103/4

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