Math, asked by ankito144, 1 year ago

solve the equation by factorization abx2 - (b2 - ac) x - bc =0

Answers

Answered by ractor
1
(bx+c) (ax-b) =0
So,x=-c/b,x=b/a
Answered by sonuvuce
2

x = -b/a, c/b

Step-by-step explanation:

abx^2+(b^2-ac)x-bc=0

or, abx^2+b^2x-acx-bc=0

or, bx(ax+b)-c(ax+b)=0

or, (ax+b)(bx-c)=0

\impies x=-\frac{b}{a}, x=\frac{c}{b}

Hope this answer is helpful.

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