Chemistry, asked by juneduran48, 1 month ago

Solve the following. 16 - 20. Find the mean of the probability distribution of the random variable x, which can take only the values 1, 2, 3 given that P(1)= 0.3 , P(2)= 0.5, and P(3)= 0.2? Compute the variance .Use the mean you get.

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Answered by GooseBumps123

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The probabilities in the probability distribution of a random variable X must satisfy the ... Solution: The possible values that X can take are 0, 1, and 2. Each of these ... P(X≥9)=P(9)+P(10)+P(11)+P(12)=436+336+236+136=1036=0.2ˉ7 ... 3. Find the mean of the discrete random variable X whose probability distribution is...The probability distribution of a discrete random variable X is a listing of each possible value x taken by X along with the probability P(x) that X takes that value in one trial of the experiment.

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Solve the following. 16 - 20. Find the mean of the probability distribution of the random variable x, which can take only the values 1, 2, 3 given that P(1)= 0.3 , P(2)= 0.5, and P(3)= 0.2? Compute the variance .Use the mean you get.​

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Solve the following. 16 - 20. Find the mean of the probability distribution of the random variable x, which can take only the values 1, 2, 3 given that P(1)= 0.3 , P(2)= 0.5, and P(3)= 0.2? Compute the variance .Use the mean you get.