Question

Solve the following

6x²+x-1=0​

Answer 1

Answer:

x = root 1/3 pls mark as brainliest

Answer 2

Solution :

$\: \: \: \: \: {6x}^{2} + x - 1 = 0$

$= > {6x}^{2} + 3x - 2x - 1 = 0$

$= > 3x(2x + 1) - 1(2x + 1) = 0$

$= > (2x + 1)(3x - 1) = 0$

$= > 2x + 1 = 0 \: \: \: \: or \: \: \: \: 3x - 1 = 0$

$= > 2x = - 1 \: \: \: \: \: or \: \: \: \: \: 3x = 1$

$= > x = \frac{ - 1}{2} \: \: \: \: or \: \: \: \: x = \frac{1}{3} .$