solve the following above question
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it is the answer........
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sheikhyousupalpcbau4:
I am Bsc
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according to the qsn ...
x²=(2+√5) +2{2²-(√5)²}½+½ +(2+√5)
=(2+√5)+2(4-5)+(2+√5)
=(2+√5)-1+2+√5
=3+2√5
same typ
y²=(2+√5)-2{2²-(√5)²}+(2-√5)
=(2+√5)-2(4-5)+(2+√5)
=2+√5+2+2+√5
=6+2√5
therefore
x²+y²=(3+2√5)+(6+2√5)
=9+4√5
=9+2².5½
=9+10^2+1/2
=9+10^5/2
I hope it help you......
plz give me brainlist marks.
x²=(2+√5) +2{2²-(√5)²}½+½ +(2+√5)
=(2+√5)+2(4-5)+(2+√5)
=(2+√5)-1+2+√5
=3+2√5
same typ
y²=(2+√5)-2{2²-(√5)²}+(2-√5)
=(2+√5)-2(4-5)+(2+√5)
=2+√5+2+2+√5
=6+2√5
therefore
x²+y²=(3+2√5)+(6+2√5)
=9+4√5
=9+2².5½
=9+10^2+1/2
=9+10^5/2
I hope it help you......
plz give me brainlist marks.
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