Question

Solve the following equation for x. 2^x+1= 4^x-3

Answer 1

Answer:

7

Step-by-step explanation:

2x+1=4x−3

log(2x+1)=log(4x−3)(Take log of both sides)

(x+1)*(log(2))=(x−3)*(log(4))

x+1=(

log(4)

log(2)

)*(x−3)

x+1=2*(x−3)

x+1=2x−6(Simplify both sides of the equation)

x+1−2x=2x−6−2x(Subtract 2x from both sides)

−x+1=−6

−x+1−1=−6−1(Subtract 1 from both sides)

−x=−7

−x

−1

=

−7

−1

(Divide both sides by -1)

x=7

Answer:

x=7

Answer 2

SOLUTION:-

${2}^{x + 1} = {4}^{x - 3}$

${2}^{x + 1} = {2}^{2x - 6}$

by comparing both sides, we get

$x + 1 = 2x - 6$

$x - 2x = - 6 - 1$

$- x = - 7$

$x = 7$

hope it will help you✔✔✔